Question

In a biprism experiment, the distance between the two images of the slits in the magnified and diminished positions are 2.4 mm and 0.6 mm respectively. The distance between the two virtual images of the slit is

• A. 1 mm
• B. 1.2 mm
• C. 2.4 mm
• D. 0.6 mm

Answer 1

The correct option is B 1.2 mm

When $1)$ magnified, distance between images, $d_1=2.4$

$2)$ dimnished, distance between images, $d_2=0.6$

$\therefore$ Distance between virtual sources

$d=\sqrt{d_1{d}_2}=\sqrt{1.44}=1.2$mm