Question

In a biprism experiment the distance between the two virtual images of the slit is $0.1$cm and the distance between the slit and screen is $1$m. If the band width is $0.058$cm. Calculate the wavelength of light.

Answer 1

Given,

The distance between the two virtual images of the slit, $d=0.1cm$

The distance between the slit and the screen, $D=1cm$

Band Width, $X=0.058cm$

We have to find out the wavelength of the monochromatic light,

That is, $\lambda =\frac{Xd}{D}$

Substituting the values in the given eqution

That is, $\lambda =\frac{0.058\times 0.1}{1}$$=0.0058cm$