Let the provisions last for ‘y' days if 20 more boys join.
Here, this is a case of inverse proportion
More the number of boys, the lesser will be the number of days that the provisions will last
So here, the product of the number of boys and the number of days will be constant.
So, 80×30=(80+20)×y
⇒y=80×30100=24
Thus, the provisions will last for 24 days