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Question

# In a Bohr's model of atom when an electron jumps from n=1 to n=3, how much energy will be emitted or absorbed

A

2.15 X 10-11 erg

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B

0.1911 X 10-10 erg

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C

2.389 X 10-12 erg

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D

0.239 X 10-10 erg

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Solution

## Step 1: FormulaΔE=−(RH)n2final−(−RH)n2initialRHisrydrberg's constantanditsvalue=2.18×10−18J ni&nf stands for initial and final orbit respectivelyStep 2: CalculationAccording to Bohr's model △E=E3−E1 ΔE=−2.18×10−18[19−1]=−2.18×10−18×−89=1.937×10−18J=1.937×10−11ergs[1J=10−7ergs]=0.1937×10−10ergs Since the electron is going from n = 1 to n = 3 hence energy is absorbed.Conclusion: Hence, option (B) is correct.

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