In a $□ A B C D$ , which of the following options is true?

A B + C D + D A > 2 A C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B + C D + D A < 2 A C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B + B C - C D - D A < 2 A C

No worries! We‘ve got your back. Try BYJU‘S free classes today!

A B + B C + C D + D A > 2 A C

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Open in App

Solution

The correct option is D $A B + B C + C D + D A > 2 A C$
In $△ A B C$ , we have sum of two sides > third side
$=> A B + B C > A C$ ...(1)
Also, in $△ A C D$ , we have sum of two sides > third side
$=> A D + C D > A C$ ...(2)
Adding equations $1, 2$ we get
$=> A B + B C + C D + A D > 2 A C$

Suggest Corrections

Similar questions

A B + B C + C D + D A > 2 A C

$In the given figure, prove that (i) CD + DA + AB > B C (ii) CD + DA + AB + BC > 2 A C .$

$A B C D$ is quadrilateral. Is $A B + B C + C D + D A < 2 (A C + B D)$ ?

A B C D

A B + B C + C D + D A < 2 (A C + B D)

A B C D

A B + B C + C D + D A > 2 A C

Join BYJU'S Learning Program