Question

In a box containing only purple and green marshmallows, $6$ marshmallows are purple. If the probability of choosing a purple marshmallow from the box is $\frac{1}{3}$, calculate the number of green marshmallows in the box.

• A. $2$
• B. $6$
• C. $9$
• D. $12$
• E. $18$

Answer 1

Answer: (D)

$12$

Given, box contains purple and green marshmallows, out of which $6$ marshmallows are purple.
Let green marshmallows be $x$
Probability of choosing purple marshmallow is $\frac{1}{3}$
We know,
Probability $=\frac{Numberoffavorableoutcomes}{Totalnumberofpossibleoutcomes}$
$\frac{1}{3}=\frac{6}{6+x}$
$18=6+x$
$x=18-6$
$x=12$
There are $12$ green marshmallows.