In a box, there are 3 blue, 4 red, and 5 green balls. What is the probability of picking up three balls such that there is 1 ball of each colour?

\frac{1}{11}

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\frac{2}{11}

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\frac{3}{11}

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\frac{4}{11}

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Solution

The correct option is C $\frac{3}{11}$

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In a box, there are 3 blue, 4 red, and 5 green balls. What is the probability of picking up three balls such that there is 1 ball of each colour?

The correct option is C 311

The correct option is C $\frac{3}{11}$