CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

In a box, there are 3 red marbles, 2 green marbles and 7 blue marbles. Oliver picks a marble blindfolded. What is the probability of picking a red marble or a green marble?

A
312
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
512
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
712
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
412
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B 512
Given:–––––––
In a box,
Number of red marbles =3
Number of green marbles =2
Number of blue marbles =7

Total number of marbles in the box =3+2+7=12

Here,
P(picking a red marble)=Number of red marblesTotal number of marbles

P(picking a red marble)=312

Next,
P(picking a green marble)=Number of green marblesTotal number of marbles

P(picking a green marble)=212

Need to Find:––––––––––––––––
Probability that the blindfoldly picked marble by Oliver is either red or green, i.e., P(picking a red marbleor a green marble)

P(picking a red marble or a green marble) = P(picking a red marble) + P(picking a green marble)

P(picking a red marble or a green marble)=312+212

P(picking a red marble or a green marble)=3+212=512

The probability of picking a red marble or a green marble is 512.

Hence, option (b.) is the correct choice.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Compound Events [ P(A or B), P( A and B) ]
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon