Question

In a box, there are 3 red marbles, 2 green marbles and 7 blue marbles. Oliver picks a marble blindfolded. What is the probability of picking a red marble or a green marble?

A
312
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B
512
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C
712
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D
412
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Solution

The correct option is B 512Given:––––––––– In a box, ∙ Number of red marbles =3 ∙ Number of green marbles =2 ∙ Number of blue marbles =7 ∴ Total number of marbles in the box =3+2+7=12 Here, P(picking a red marble)=Number of red marblesTotal number of marbles ⇒P(picking a red marble)=312 Next, P(picking a green marble)=Number of green marblesTotal number of marbles ⇒P(picking a green marble)=212 Need to Find:–––––––––––––––––– Probability that the blindfoldly picked marble by Oliver is either red or green, i.e., P(picking a red marbleor a green marble) P(picking a red marble or a green marble) = P(picking a red marble) + P(picking a green marble) ⇒P(picking a red marble or a green marble)=312+212 ⇒P(picking a red marble or a green marble)=3+212=512 ∴ The probability of picking a red marble or a green marble is 512. Hence, option (b.) is the correct choice.

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