Question

In a box there are $5$ black pens,$3$ white pens and $4$ red pens. In how many ways can $2$ black pens,$2$ white pens and $2$ red pens can be chosen?

• A. $160$
• B. $120$
• C. $180$
• D. $144$

Answer 1

The correct option is C $180$

There are $5$ black pens , $3$ white pens and $4$ red pens.

We have to select $2$ black pens , $2$ white pens and $2$ red pens.

Therefore ,${}^5{C}_2{\times }^3{C}_2{\times }^4{C}_2=180$