Question

In A.C. circuit in which inductance and capacitance are joined in series, current is found to be maximum when the value of inductance is $0.5H$ and the value of capacitance is $8\mu F$. The angular frequency of applied alternating voltage will be

• A. 400 Hz
• B. 500 Hz
• C. 4000 Hz
• D. 5000 Hz

Answer 1

The correct option is B 500 Hz

Given,

Inductance and capacitance are joined in series, and inductance $L=0.5H$,

And capacitance $C=8\mu F=8\times {10}^{-6}F$.

We know that,

$\omega =\frac{1}{\sqrt{LC}}$

$\omega =\frac{1}{\sqrt{8\times {10}^{-6}\times 0.5}}=\frac{1}{2\times {10}^{-3}}=0.5\times {10}^{3}HZ=500HZ$