Question

In a calendar year, the $8$ members of a football team had the following scores: $32,40,48,52,64,68,73,70$
What is the right way to interpret the median score?

• A. Median = 58. It is the middle point in the set of scores. That is, four footballers scored higher than the median, and four footballers scored lower than the median.
• B. Median= 58. It is the "average" score. That is, if each footballer had scored the same, they each would have scored the median.
• C. Median = 58. It is the median score made by each player, which is the most frequently repeated score.
• D. None of the above

Answer 1

The correct option is A Median = 58. It is the middle point in the set of scores. That is, four footballers scored higher than the median, and four footballers scored lower than the median.

Arranging the scores in increasing orders
$32,40,48,52,64,68,73,70\Rightarrow 32,40,48,52,64,68,70,73$
Median $=\frac{52+64}{2}=\frac{116}{2}=58$

Four of the eight footballer were below the median and the other four were above.

Answer:
$\Rightarrow$ It is the middle point in the set of scores. That is, half the team scored higher than the median, and half the team scored lower than the median.