In a capillary tube, water rises to a height of 4 cm. If the cross sectional area of the tube were one – fourth, water would have raised to a height of
8 cm
Cross sectional area of the tube, A =πr2
Height of capillary rise is given by, h=2τρgr⇒h∝1r
But r∝√A . Hence h∝1r⇒h1h2=√A2A1=√14
∴ h2=2h1=8 cm