In a Carnot engine- when T 2-0- C and T 1-200- C- its efficiency is -1 and when T 1-0- C and T 2-200- C- Its efficiency is -2- then what is -1-2A- 0-577B- 0-733C- 0-638D- Can not be calculated

The correct option is A 0.577 η = 1 T_2/T_1 = T_1 T_2/T_1⇒η_1 = (473 273)/473 = 200/473 and η_2 = 273 73/273 = 200/273 So required ratio η_1/η_2 = 273/ ...

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Standard X

Physics

Relation Between MA and VR

In a Carnot e...

Question

In a Carnot engine, when $T_{2} = 0^{\circ} C$ and $T_{1} = 200^{\circ} C$ , its efficiency is $η_{1}$ and when $T_{1} = 0^{\circ} C$ and $T_{2} = - 200^{\circ} C$ , Its efficiency is $η_{2}$ , then what is $\frac{η_{1}}{η_{2}}$

0.577

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0.733

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0.638

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Can not be calculated

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Solution

The correct option is A
0.577

$η = 1 - \frac{T_{2}}{T_{1}} = \frac{T_{1} - T_{2}}{T_{1}} \Rightarrow η_{1} = \frac{(473 - 273)}{473} = \frac{200}{473}$

and $η_{2} = \frac{273 - 73}{273} = \frac{200}{273}$

So required ratio $\frac{η_{1}}{η_{2}} = \frac{273}{473} = 0.577$

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In a Carnot engine, when T2=0∘C and T1=200∘C, its efficiency is η1 and when T1=0∘C and T2=−200∘C, Its efficiency is η2, then what is η1η2

The correct option is A 0.577 η=1−T2T1=T1−T2T1⇒η1=(473−273)473=200473 and η2=273−73273=200273 So required ratio η1η2=273473=0.577

In a Carnot engine, when $T_{2} = 0^{\circ} C$ and $T_{1} = 200^{\circ} C$ , its efficiency is $η_{1}$ and when $T_{1} = 0^{\circ} C$ and $T_{2} = - 200^{\circ} C$ , Its efficiency is $η_{2}$ , then what is $\frac{η_{1}}{η_{2}}$

The correct option is A
0.577

$η = 1 - \frac{T_{2}}{T_{1}} = \frac{T_{1} - T_{2}}{T_{1}} \Rightarrow η_{1} = \frac{(473 - 273)}{473} = \frac{200}{473}$

and $η_{2} = \frac{273 - 73}{273} = \frac{200}{273}$

So required ratio $\frac{η_{1}}{η_{2}} = \frac{273}{473} = 0.577$