wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a Carnot engine, when T2=0C and T1=200C, its efficiency is η1 and when T1=0C and T2=200C, Its efficiency is η2, then what is η1 /η2

A
0.577
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
0.733
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
0.638
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Can not be calculated
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A 0.577
Using the efficiency of carnot cycle
η=1T2T1η1=(473273)473=200473 and η2=27373273=200273
so required ratio η1η2=273473=0.577

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Viscosity
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon