In a CE amplifier - - 50- RL - 4K- R1 - 500- Power gain of the amplifier is-

The correct option is A 2× 10^4 Voltage gain V=50×4000500=400 current gain I=β=50 power gain=VI=2× 10^4 ...

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Standard XII

Physics

The Photon Model

In a CE amp...

Question

In a $C E$ amplifier $β = 50, R_{L} = 4 K Ω . R_{1} = 500 Ω$ . Power gain of the amplifier is.

2 \times 10^{4}

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2 \times 10^{2}

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2 \times 10^{3}

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2 \times 10^{1}

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Solution

The correct option is A $2 \times 10^{4}$
Voltage gain $V = \frac{50 \times 4000}{500} = 400$
current gain $I = β = 50$
$p o w e r g a i n = V I = 2 \times 10^{4}$

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In a CE amplifier β=50,RL=4KΩ.R1=500Ω. Power gain of the amplifier is.

The correct option is A 2×104Voltage gainV=50×4000500=400current gain I=β=50powergain=VI=2×104

In a $C E$ amplifier $β = 50, R_{L} = 4 K Ω . R_{1} = 500 Ω$ . Power gain of the amplifier is.

The correct option is A $2 \times 10^{4}$
Voltage gain $V = \frac{50 \times 4000}{500} = 400$
current gain $I = β = 50$
$p o w e r g a i n = V I = 2 \times 10^{4}$