In a $C E, n - p - n$ transistor circuit, the emitter current is

More than the collector current

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Less than the collector current

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Less than the base current

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Equal to the difference of the collector current and the base current

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Solution

The correct option is A More than the collector current
In $n - p - n$ transistor as $C E$ amplifier
$i_{e} = i_{b} + i_{c}$
Where, $I_{e} = e m i i t e r c u r r e n t$
$I_{b} = b a s e c u r r e n t$
$I_{c} = c o l l e c t o r c u r r e n t$
Therefore, the emitter current is more than the collector current.

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In a CE,n−p−n transistor circuit, the emitter current is

The correct option is A More than the collector currentIn n−p−n transistor as CE amplifierie=ib+icWhere, Ie=emiiter current Ib=base current Ic=collector currentTherefore, the emitter current is more than the collector current.

In a $C E, n - p - n$ transistor circuit, the emitter current is