In a cell - the following reaction takes place-Fes-CuSO4aq- FeSO4aq-CusThe correct cell representation is-

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Nersnt Equation

In a cell , t...

Question

In a cell , the following reaction takes place:

$F e (s) + C u S O_{4} (a q) \to F e S O_{4} (a q) + C u (s)$

The correct cell representation is:

C u (s) | C u^{2 +} (a q) | | F e (s) | F e^{2 +} (a q)

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C u^{2 +} (a q) | C u (s) | | F e^{2 +} (a q) | F e (s)

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F e (s) | F e^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)

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C u^{2 +} (a q) | C u (s) | | F e (s) | F e^{2 +} (a q)

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Solution

The correct option is C $F e (s) | F e^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)$
Since in the given reaction:

$F e (s)$ is getiing oxidised to $F e^{2 +} (a q)$
So, it is at anode, and must be represented at left side during cell representation.
Also,
$C u^{2 +} (a q)$ is getiing reduced to $C u (s)$
So, it is at cathode , and must be represented at right side during cell representation.
Both representations are seperated by $| |$ which indicates a salt bridge.
The correct cell representation is :
$F e (s) | F e^{2 +} (a q) | | C u^{2 +} (a q) | C u (s)$

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Similar questions

Which of the following reactions will not occur ? Why not?
(a) $M g S O_{4} (a q) + C u (s) ⟶ C u S O_{4} (a q) + M g (s)$
(b) $C u S O_{4} (a q) + F e (s) ⟶ F e S O_{4} (a q) + C u (s)$
(c) $M g S O_{4} (a q) + F e (s) ⟶ F e S O_{4} (a q) + M g (s)$