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Question

In a certain A.P. the 24th term is twice the 10th term. Prove that the 72nd term is twice the 34th term.

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Solution

Here, we are given that 24th term is twice the 10th term, for a certain A.P. Here, let us take the first term of the A.P. as a and the common difference as d

We have to prove that

So, let us first find the two terms.

As we know,

For 10th term (n = 10),

For 24th term (n = 24),

Now, we are given that

So, we get,

Further, we need to prove that the 72nd term is twice of 34th term. So let now find these two terms,

For 34th term (n = 34),

(Using 1)

For 72nd term (n = 72),

(Using 1)

Therefore,


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