In a certain Bohr orbit, the total energy is $- 4.9 e V$ . For this orbit, the kinetic energy, and potential energy are respectively:

9.8 e V, - 4.9 e V

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4.9 e V, - 9.8 e V

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4.9 e V, - 4.9 e V

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9.8 e V, - 9.8 e V

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Solution

The correct option is B $4.9 e V, - 9.8 e V$
Potential Energy, $P E = - k Z e^{2} / r$ , whereas $K E = 1 / 2 \times m v^{2}$ .
According to Bohr's Model, $m v^{2} / r = k Z e^{2} / r^{2}$ , therefore $1 / 2 \times m v^{2} = k Z e^{2} / 2 r$ .
$K E = - P E / 2$ .
$T o t a l E n e r g y = - 4.9$
$K . E + P o t e n t i a l E n e r g y = T o t a l E n e r g y$
$K . E = 4.9 e v = (- t o t a l E n e r g y)$
$P . E = 2 [t o t a l E n e r g y] = - 9.8 e v$

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