In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 5 rows in all and a total of 75 bricks in the wall, how many bricks does the bottom row contain?

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Solution

The correct option is C 17
Let x bricks be there in the bottom row.
Given that x+(x-1) +(x-2) +(x-3) +(x-4) = 75;
$\Rightarrow x = 17$

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In a certain brick wall, each row of bricks above the bottom row contains one less brick than the row just below it. If there are 5 rows in all and a total of 75 bricks in the wall, how many bricks does the bottom row contain?

The correct option is C 17Let x bricks be there in the bottom row. Given that x+(x-1) +(x-2) +(x-3) +(x-4) = 75; ⇒x=17

The correct option is C 17
Let x bricks be there in the bottom row.
Given that x+(x-1) +(x-2) +(x-3) +(x-4) = 75;
$\Rightarrow x = 17$