Question

In a certain circuit current changes with time according to $i=2\sqrt{t}.$ r.m.s. value of current between t=2 to t=4s will be

• A. 3A
• B.
  
• C.
  
• D.
  

Answer 1

The correct option is C

$\overline{i^2}=\frac{\int i^{2}dt}{\int dt}=\frac{{\int }_2^4\left(4t\right)dt}{{\int }_2^{4}dt}=\frac{4{\int }_2^{4}tdt}{2}=2{\left[\frac{t^2}{2}\right]}_2^4={\left[t^2\right]}_2^4=12\Rightarrow i_{rm1}=\sqrt{\overline{i^2}}=\sqrt{12}=2\sqrt{3}A$