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Question

In a certain code language, codes are decided on the basis of following rules and conditions.

Rules:
1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(B =0, C =1, D= 2 and so on)
2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(P = 0, Q=1, R=2 and so on)
3. ‘N’ is to be coded as 1.

Conditions:
I. If a word starts with a vowel but ends with a consonant then all the vowels of that word are to be coded as ‘@’ and codes for last and first letters will be interchanged.
II. If a word has more than two vowels then the first vowel is to be coded as *, second vowel as +, third vowel as -, and then repeat the codes in the same sequence from fourth vowel onwards.
III. If in a word a consonant that appears right after P is followed by a vowel then all the vowels of that word are to be coded as ‘!’ and 1 is subtracted from the original code of all consonants.
IV. If none of the above conditions are applicable in a word then vowels of such word are coded as ‘#‘.
V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.

Q. What is the code for EMPHASIS

A
3905@3@@
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B
!804!2!@
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C
!804!2!!
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D
@905+3-@
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E
None of these
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Solution

The correct option is B !804!2!@
Code for consonants before N

Now comparing the word EMPHASIS with the conditions given.
We notice that the word satisfies all the conditions except condition IV so we will 1st code the word as per the rule then apply the conditions one by one.
Applying the rule EMPHASIS
= _905_3_3
Applying condition 1
= 3905@3@@
Applying condition 2
= @905+3-@
Applying condition 3
= !804!2!@

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