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Question

In a certain code language, codes are decided on the basis of following rules and conditions.

Rules:
1. All the consonants that appear before ‘N’ in alphabet series are to be coded as 0-9.(B =0, C =1, D= 2 and so on)
2. All the consonants that appear after ‘N’ in alphabet series are to be coded as 0-9.(P = 0, Q=1, R=2 and so on)
3. ‘N’ is to be coded as 1.

Conditions:
I. If a word starts with a vowel but ends with a consonant then all the vowels of that word are to be coded as ‘@’ and codes for last and first letters will be interchanged.
II. If a word has more than two vowels then the first vowel is to be coded as *, second vowel as +, third vowel as -, and then repeat the codes in the same sequence from fourth vowel onwards.
III. If in a word a consonant that appears right after P is followed by a vowel then all the vowels of that word are to be coded as ‘!’ and 1 is subtracted from the original code of all consonants.
IV. If none of the above conditions are applicable in a word then vowels of such word are coded as ‘#‘.
V. If more than one condition is applicable in a single word then apply all the conditions as per the given order.

Q. What is the code for the word KINGDOM

A
@#14278
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B
7#142#9
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C
6!232!9
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D
7@142@9
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E
None of these
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Solution

The correct option is B 7#142#9
Code for consonants before N
Code for consonants after N

The word kingdom doesn’t satisfy any of the conditions given, so we code the word and apply condition V.
Applying the code
KINGDOM
= 7_142_9
Applying condition IV
= 7#142#9

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