In a certain code language if GOD is coded as 6 - 8 - 14 - 16 - 3 - 5 then BEN is coded as

1 - 3 - 4 - 6 - 13 - 15

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1 - 2 - 4 - 6 - 13 - 15

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1 - 3 - 4 - 5 - 13 - 15

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1 - 3 - 4 - 6 - 14 - 25

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Solution

The correct option is A 1 - 3 - 4 - 6 - 13 - 15
Opt A is the correct answer.

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Similar questions

Q. In a certain code language if

3 + 3 = 9

6 - 3 = 2

4 \times 3 = 1

3 \div 2 = 5

, then find the value of

5 + 4 \div 24 - 8 \times 6

in the same code language?

Find the sum:
(i) 2+4+6+...+200
(ii) 3+11+19+...+803
(iii) (-5)+(-8)+(-11)+...+(-230)
(iv) 1+3+5+7+...+199
(v) $7 + 10 \frac{1}{2} + 14 + . . . + 84$
(vi) 34+32+30+...+10
(vii) 25+28+31+...+100
(viii) $18 + 15 \frac{1}{2} + 13 + . . . + (- 49 \frac{1}{2})$

Q. In a certain code language if

3 + 3 = 9, 6 - 3 = 2, 4 \times 3 = 1, 3 \div 2 = 5

, then find

24 \times 6 \div 8 - 2 + 3 = ?

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

Q. If

5 \times 9 = 144; 7 \times 8 = 151 : 4 \times 6 = 102,

then

2 \times 5 = ?

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In a certain code language if GOD is coded as 6 - 8 - 14 - 16 - 3 - 5 then BEN is coded as

The correct option is A 1 - 3 - 4 - 6 - 13 - 15Opt A is the correct answer.

The correct option is A 1 - 3 - 4 - 6 - 13 - 15
Opt A is the correct answer.