In a certain electronic transition in the hydrogen atom from an initial state (1) to a final state (2), the difference in the orbital radius $(r_{1} - r_{2})$ is 24 times the first Bohr radius. Identify the transition:

5 \to 1

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25 \to 1

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8 \to 3

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1 \to 5

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Solution

The correct option is A $5 \to 1$
$r a d i u s \propto \frac{n^{2}}{Z}$
Now, $r_{n 2} - r_{n 1} = 24 \times r_{0}$ .
$∴ n_{2}^{2} - n_{1}^{2} = 24$
Possible solutions $n_{2} = 7, n_{1} = 5 o r n_{2} = 5, n_{1} = 1$ .

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In a certain electronic transition in the hydrogen atom from an initial state (1) to a final state (2), the difference in the orbital radius (r1−r2) is 24 times the first Bohr radius. Identify the transition:

The correct option is A 5→1radius∝n2ZNow, rn2−rn1=24×r0.∴n22−n21=24Possible solutions n2=7,n1=5orn2=5,n1=1.

In a certain electronic transition in the hydrogen atom from an initial state (1) to a final state (2), the difference in the orbital radius $(r_{1} - r_{2})$ is 24 times the first Bohr radius. Identify the transition:

The correct option is A $5 \to 1$
$r a d i u s \propto \frac{n^{2}}{Z}$
Now, $r_{n 2} - r_{n 1} = 24 \times r_{0}$ .
$∴ n_{2}^{2} - n_{1}^{2} = 24$
Possible solutions $n_{2} = 7, n_{1} = 5 o r n_{2} = 5, n_{1} = 1$ .