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Question

In a certain parallel resonant band-pass filter, the resonant frequency is 14 kHz. If the bandwidth is 4 kHz, the lower frequency is

A
6 kHz
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B
16 kHz
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C
12 kHz
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D
Cannot be determined
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Solution

The correct option is D 12 kHz
Given that resonance frequency is 14kHz and the bandwidth is 4kHz
We know that bandwidth is equal to twice the frequency of signal
B=2×f
4=2×f
So the signal frequency f=42=2
Therefore the higher frequency is 14+2=16kHz and the lower frequency is 142=12kHz
Therefore option C is correct

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