In a certain plant, the genes for purple flowers and tall height, (AB) is incompletely dominant over the genes for white flowers and dwarf height (ab). What is the expected phenotypic ratio of the offspring, in a cross involving AaBb×AaBb parents?
A
1:1:1:1
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B
9:3:3:1
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C
3:6:3:1:2:1
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D
1:2:1:2:4:2:1:2:1
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Solution
The correct option is D1:2:1:2:4:2:1:2:1 The cross will be similar to the Mendelian dihybrid cross but the ratio will be different due to the incomplete dominance of alleles over each other, thus giving rise to two new phenotypes of flower colour and plant height. Let's consider them to be a purple colour and medium height. Then on solving the Punnett square we will get a phenotypic ratio of 1:2:1:2:4:2:1:2:1 for the phenotypes purple,tall: purple,medium: purple,short: blue,tall: blue,medium: blue,short: white,tall: white,medium: white,short.