In a certain reaction, 10% of the reactant decomposes in one hour, 20% in two hours. 30% in three hours and so on the dimensions of the rate constant is:
A
hour−1
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B
molelitre−1sec−1
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C
litremole−1sec−1
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D
molesec−1
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Solution
The correct option is Cmolelitre−1sec−1 Given reaction is a zero order reaction because on plotting the percent decomposition of reaction as time, we will obtain a straight line.
A straight line is a characteristic of a zero order reaction.
Since K=xt for a zero order reaction its units are mol/L.sec.