CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

In a certain region of space, electric field is along the z-direction throughout. The magnitude of electric field is, however, not constant but increases uniformly along the positive z-direction, at the rate of 105NC1 m1 per metre. What are the force and torque experienced by a system having a total dipole moment equal to 107 Cm in the negative z-direction ?

Open in App
Solution

Dipole moment of the system, p=q×dl=107Cm

Rate of increase of electric field per unit length,

dEdl=10+5NC1

Force (F) experienced by the system is given by the relation,

F=qE

F=qdEdl×dl

=p×dEdl

=107×105

=102N

The force is 102N in the negative z-direction i.e., opposite to the direction of electric field. Hence, the angle between electric field and dipole moment is 180o.

Torque (τ) is given by the relation,

T=pEsin180o=0

Therefore, the torque experienced by the system is zero.


flag
Suggest Corrections
thumbs-up
1
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Motional EMF
PHYSICS
Watch in App
Join BYJU'S Learning Program
CrossIcon