In a certain region of space with volume $0.2 m^{3}$ , the electric potential is is found to be $5 V$ throughout. The magnitude of electric in this region is

Zero

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.5 {NC}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

1 {NC}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5 {NC}^{- 1}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Zero
Since electric potential is constant throughout the volume, hence electric field,

$E = - \frac{d V}{d r} = 0$

 Hence, (a) is the correct answer.

Suggest Corrections

Similar questions

Q. In a certain region of space with volume

0.2 m^{3}

, the electric potential is found to be

5 V

throughout. The magnitude of electric field in this region is :

Q. In a certain

0.5 c m^{3}

of space electric potential is found to be

7 V

throught. What is the electric field in this region?

The electric potential in a certain region of space is given by $v = - 3 x^{2} + 4 x$ , where x is in metres and v is in volts. In this region, the equipotential surfaces are

Q. In a certain region of space, the potential is given by

V = k [2 x^{2} - y^{2} + z^{2}]

. The electric field at the point

(1, 1, 1)

has magnitude=

Q. Electric potential in a particular region of space is

V = 12 x - 3 x^{2} y + 2 y z^{2}

. The magnitude of electric field at point

P (1 m, 0, - 2 m)

N / C

Join BYJU'S Learning Program

In a certain region of space with volume 0.2 m3, the electric potential is is found to be 5 V throughout. The magnitude of electric in this region is

The correct option is A ZeroSince electric potential is constant throughout the volume, hence electric field, E=−dVdr=0  Hence, (a) is the correct answer.

In a certain region of space with volume $0.2 m^{3}$ , the electric potential is is found to be $5 V$ throughout. The magnitude of electric in this region is

The correct option is A Zero
Since electric potential is constant throughout the volume, hence electric field,

$E = - \frac{d V}{d r} = 0$

 Hence, (a) is the correct answer.