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Question

In a certain region, uniform electric field exists as E=E0^j. A proton and an electron are projected from origin at time t=0 with certain velocities along +x-axis direction. Due to the electric field, they experience force and move in the xy-plane along different trajectories.

(iii) If they have the same initial velocity then for the same displacement along x axis, displacement along y axis is

A
more for proton
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B
more for electron
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C
equal for both
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D
independent of kinetic energy
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Solution

The correct option is B more for electron
As, electric field exist along the y-axis,

ax=0 and ay=qEm

Let initial velocity along the x-axis be ux=v0

Displacement along the x-axis is,
x=v0t t=xv0

Displacement along the y-axis is,

y=12at2=qEt22m

y=qEx22m(v0)2

y1m

mass of the proton (mp)>mass of the proton(me)

Hence, the deflection of the electron is greater than the deflection of the proton.

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, (B) is the correct answer.

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