Question

In a certain town $40$% of the people have brown hair, $25$% have brown eyes and $15$% have both brown hair and brown eyes. If a person selected at random from the town, has brown hair, the probability that he also has eyes is-

• A. 1/5
• B. 3/8
• C. 1/3
• D. 2/3

Answer 1

Answer: (B)

3/8

Let $BE=$ Brown eyes, $BH=$ Brown hair.

According to the question,

$\therefore P\left(BH\right)=\frac{40}{100}=0.4$

$P\left(BE\right)=\frac{25}{100}=0.25$

$P\left(BHandBE\right)=\frac{15}{100}=0.15$

$\therefore P\left(\frac{BH}{BE}\right)=\frac{P\left(BHandBE\right)}{P\left(BE\right)}=\frac{0.15}{0.4}=\frac{15}{40}=\frac{3}{8}$