In a certain town , 60% of the families own a car, 30% own a house and 20% own both a car and a house. If a family is randomly chosen, what is the probability that this family owns a car or a house but not both?
A
0.5
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B
0.7
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C
0.1
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D
0.9
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Solution
The correct option is A0.5 Probability that the family owns a car is P(A)=0.6 Probability that the family owns a house is P(B)=0.3 Probability that the family owns both a house and a car is P(A∩B)=0.2
∴ The probability that the family owns a car or a house but not both is P(A∪B)−P(A∩B)=0.6+0.3−0.2−0.2=0.5 Thus, the probability that this family owns a car or a house but not both is 0.5.