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Conditional Probability

In a certain ...

Question

In a certain town, $60$ % of the families own a car, $30$ % own a house and $20$ % own both a car and a house.If a family is randomly chosen, what is the probability that this family owns a car or a house but not both?

A

0.5

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B

0.7

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C

0.1

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D

0.9

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Solution

The correct option is A $0.5$
$A = C a r; B = H o u s e$
$P (A Δ B) = P (A \cup B) - P (A \cap B)$
$= \frac{70 - 20}{100} = 0.5$

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