In a certian A.P. the 24th term is twice the 10th term. Prove that the 72nd term is twice the 34th term.
Let the first term and the common difference be "a" and "d"
Given. T24 = 2 T10
or, a + 23d = 2(a + 9d)
= 2a + 18d
or, a = 5d ……………… (i)
Now, T34 = a + 33d
= 5d + 33d Using (i)
= 38d ............. (ii)
T72 = a + 71d
= 5d + 71d Using (i)
= 76d
= 2 x 38d
= 2 x T34 Using (ii)