Question

In a change form $PC{l}_3\to PC{l}_5$, the hybrid state of $P$ changes form:

• A. $s{p}^{2}tos{p}^3$
• B. $s{p}^{3}tos{p}^2$
• C. $s{p}^{3}tos{p}^{3}d$
• D. $s{p}^{3}tods{p}^2$

Answer 1

Answer: (C)

$s{p}^{3}tos{p}^{3}d$

$PC{l}_3\to PC{l}_5$ : $P$ initiallly had $3$ bond pairs and $1$ lone pair making it $s{p}^3$ but later it has $5$ bond pairs making it $s{p}^{3}d$