In a chemistry lab- 2 reactions are taking place each in 2 beakers- One at 149- F R 1 and another at 70- C R 2 - Which reaction occurs at a higher temperature-A- R 2B- both occur at same temperatureC- cannot sayD- R 1

The correct option is A R_2 R_1 ^∘ C = (^∘ F 32)×5/9 ^∘ F = 149 ^∘ C = (149 32)×5/9=117×5/9 ^∘ C = 13 × 5 = 65^∘ C R_1 proceeds at 65^∘ C R_2 proceeds at 70^∘ ...

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Standard V

Mathematics

Measuring Temperature

In a chemistr...

Question

In a chemistry lab, 2 reactions are taking place each in 2 beakers. One at $149^{\circ} F$ ( $R_{1}$ ) and another at $70^{\circ} C$ ( $R_{2}$ ). Which reaction occurs at a higher temperature?

$R_{1}$

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$R_{2}$

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both occur at same temperature

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cannot say

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Solution

The correct option is B
$R_{2}$

$R_{1}^{\circ} C = (^{\circ} F - 32) \times \frac{5}{9}$

$^{\circ} F$ = 149

$^{\circ} C = (149 - 32) \times \frac{5}{9} = 117 \times \frac{5}{9}$

$^{\circ} C$ = 13 $\times$ 5 = $65^{\circ} C$

$R_{1}$ proceeds at $65^{\circ} C$

$R_{2}$ proceeds at $70^{\circ} C$

Answer : $R_{2}$ at $70^{\circ} C$ is at a higher temperature

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In a chemistry lab, 2 reactions are taking place each in 2 beakers. One at 149∘ F (R1) and another at 70∘ C (R2). Which reaction occurs at a higher temperature?

The correct option is B R2 R1 ∘C = (∘F−32)×59 ∘F = 149 ∘C = (149−32)×59=117×59 ∘C = 13 × 5 = 65∘ C R1 proceeds at 65∘ C R2 proceeds at 70∘ C Answer : R2 at 70∘ C is at a higher temperature

In a chemistry lab, 2 reactions are taking place each in 2 beakers. One at $149^{\circ} F$ ( $R_{1}$ ) and another at $70^{\circ} C$ ( $R_{2}$ ). Which reaction occurs at a higher temperature?