Question

In a chess tournament, where the participants were to play one game with another.If the total number of games played is 91, the number of participants in the tournament are

• A. $11$
• B. $12$
• C. $13$
• D. $14$

Answer 1

Answer: (D)

$14$

Let number of participants be $n$, and it given that participants were to play one game with another
Hence number of game is $=$ selection any two players out of $n$ which is, ${}^n{C}_2=91$ (given)
$\Rightarrow n(n-1)=2\times 91=182=14\times 13\Rightarrow n=14$