Question

In a circle of diameter 10 cm, the length of each of 2 equal and parallel chords is 8 cm, then the distance between these two chords is

• A. 4 cm
• B. 5 cm
• C. 6 cm
• D. 7 cm

Answer 1

The correct option is C 6 cm

Given the diameter of circle is 10 cm and two equal cord length is 8 cm

Then radius of cord =$\frac{10}{2}=5$ cm

And half of cord =$\frac{8}{2}=4$ cm

As per Pythagoras formula

Distance of cord from center of circle=$\sqrt{(5{)}^2-(4{)}^2}=\sqrt{25-16}=\sqrt{9}=3$ cm

And Distance of cord from center of circle=$\sqrt{(5{)}^2-(4{)}^2}=\sqrt{25-16}=\sqrt{9}=3$ cm

Then distance of both cord =3+3=6 cm