In a circle of diameter 40 cm, the length of a chord is 20 cm. Find the length of minor arc of the chord.
The circle diameter is 40 cm .
The length of the chord is 20 cm .
The radius of the circle is
Radius = Diameter 2 = 40 2 = 20 cm
The radius is equal to the length of the chord. Thus, the two radii lines along with the chord form an equilateral triangle. It is known that for equilateral triangle all angles are π 3 radian . Thus, the angle subtended at the centre is π 3 radian .
The length of the arc is
Length of the arc = ( Angle subtended ) × ( Radius of the circle ) = π 3 × 20 = 20.94 m
Thus, the length of the minor arc is, 20 π 3 = 20.94 m
The circle diameter is
The length of the chord is
The radius of the circle is
The radius is equal to the length of the chord. Thus, the two radii lines along with the chord form an equilateral triangle. It is known that for equilateral triangle all angles are
The length of the arc is
Thus, the length of the minor arc is,
