Question

In a circle of radius 10 cm length, a chord subtends right-angle at the centre, then the length of the chord is

• A. $10\sqrt{2}$
• B. 10
• C. 20
• D. $10\sqrt{5}$

Answer 1

The correct option is A

$10\sqrt{2}$

Chord AB subtneds right angle at centre O using pythogorus theorem we get

$A{B}^2=A{O}^2+O{B}^{2}A{B}^2={10}^2+{10}^2=200AB=10\sqrt{2}m$