In a circle of radius $13$ cm, $P Q$ and $R S$ are two parallel chords of length $24$ cm and l0cm respectively. The chords are on the opposite sides of the centre. The distance between the chords is?

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Solution

The correct option is B $17$ cm
Distance between chords = OB + OA = AB

$R S = 10 ⟹ B S = 5$

$P Q = 24 ⟹ A Q = 12$

$O S = O Q = 13 c m (r a d i u s)$

$O B = \sqrt{O S^{2} - B S^{2}} = 12 c m$

$O A = \sqrt{O S^{2} - A S^{2}} = 5 c m$

$A B = 17 c m$

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Similar questions

$P Q$ and $R S$ are two parallel chords of a circle such that $P Q = 10 c m$ & $R S = 24 c m$ . If the chords are on the opposite sides of the centre and the distance between them is $17 c m$ , find the radius of the circle.

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In a circle of radius 13cm, PQ and RS are two parallel chords of length 24cm and l0cm respectively. The chords are on the opposite sides of the centre. The distance between the chords is?

The correct option is B 17cmDistance between chords = OB + OA = AB RS=10⟹BS=5 PQ=24⟹AQ=12 OS=OQ=13cm(radius) OB=√OS2–BS2=12cm OA=√OS2–AS2=5cm AB=17cm

In a circle of radius $13$ cm, $P Q$ and $R S$ are two parallel chords of length $24$ cm and l0cm respectively. The chords are on the opposite sides of the centre. The distance between the chords is?

The correct option is B $17$ cm
Distance between chords = OB + OA = AB

$R S = 10 ⟹ B S = 5$

$P Q = 24 ⟹ A Q = 12$

$O S = O Q = 13 c m (r a d i u s)$

$O B = \sqrt{O S^{2} - B S^{2}} = 12 c m$

$O A = \sqrt{O S^{2} - A S^{2}} = 5 c m$

$A B = 17 c m$