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Byju's Answer
Standard IX
Mathematics
Theorem 1: Equal Chords Subtend Equal Angles at the Center
In a circle o...
Question
In a circle of radius 13cm, two chords MN and JK are at a distance of 5cm from the centre. Find the measure of (MN + 2×JK)
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Solution
Draw two radii MO and JO
Applying Pythagoras theorem:
OM
2
= OP
2
+ MP
2
13
2
= 5
2
+ MP
2
MP
2
= 169 − 25 = 144
MP = 12
∴ MP = PN = 12 cm
MN = 24 cm
∴ MN = JK = 24 cm
MN + 2×JK = (24 + 48) cm = 72 cm
Answer: MN + 2×JK = 72 cm
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Q.
In a circle with radius 13 cm, two equal chords are at a distance of 5 cm from the centre. Find the lengths of the chords.