In a circle of radius 17 cm, two parallel chords are drawn on opposite sides of a diameter. The distance between the chords is 23 cm. If the length of one chord is 16 cm, then the length of the other is
30 cm
Given that
OB = OD =17
AB = 16 ⇒ AE = BE = 8 cm as perpendicular from center to the chord bisects the chords
EF = 23 cm
Consider △OEB
OE2 = OB2 - EB2
OE2 = 172 - 82
OE = 15 CM
OF = EF - OE
OF = 23 - 15
OF = 8 cm
FD2 = OD2 - OF2
FD2 = 172 - 82
FD = 15
Therefore CD = 2FD = 30 cm