In a circle of radius 7 cm, AB and QC are two equal chords. If the line joining the points B and Q passes through the centre of the circle then find the length of the line joining B and Q.

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Solution

Lets observe the diagram first.
The line joining B and Q passes through the centre and also touches the boundary of the circle at both the ends.
Line BQ is the diameter of the circle.
So Diameter BQ = 2 x Radius = 2 x 7 cm = 14 cm

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In a circle of radius 7 cm, AB and QC are two equal chords. If the line joining the points B and Q passes through the centre of the circle then find the length of the line joining B and Q.

Lets observe the diagram first. The line joining B and Q passes through the centre and also touches the boundary of the circle at both the ends. Line BQ is the diameter of the circle. So Diameter BQ = 2 x Radius = 2 x 7 cm = 14 cm

Lets observe the diagram first.
The line joining B and Q passes through the centre and also touches the boundary of the circle at both the ends.
Line BQ is the diameter of the circle.
So Diameter BQ = 2 x Radius = 2 x 7 cm = 14 cm