In a circle with centre O. Chords PQ and RS intersect at right angles at point A inside the circle. Prove that PQ2 + RS2 = 4[2PO2 - OA2] .

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Solution

There is no mentioning of point A in the question and also figure not given.
So how can we solve the question?
Plz submit the question more clearly next time.If figure is given,provide that also.

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