In a circle with centre O, two unequal chords PQ and RS intersect each other at M, then ΔPMR and ΔQMS are
A
congruent
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B
equal in area
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C
similar
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D
none of these
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Solution
The correct option is C similar For △PMS and △SMQ 1.∠PMR=∠QMS (Vertically opposite angle) 2.∠MPR=∠MSQ (Angle subtended by the same arc are equal) 3.∠MRP=∠MQS (Sum property of △). Thus By AAA criteria △PMS≈△SMQ. ANS- Option C