The equation through loop I1 is
−2+3I1+1+2(I1−I2)=0
The equation through loop I2 is
−3+4I2+1+2(I2−I1)=0
On solving we get
I1=513A
I2=613A
Current through 2Ω will be I1−I2=113A
Potential difference between points B and D will be
V=IR
=(113×2)V
=213V
The potential difference between G and H will also be same as that of between B and D.