Question

In a circuit having one bulb, another bulb is added in series. Then the bulbs will :

• A. not glow
• B. glow but less brightly
• C. glow more brightly
• D. get fused

Answer 1

Answer: (B)

glow but less brightly

Adding Load in series reduce the voltage on each load which actually sums upto the Voltage of the Source itself.

Here in this case we added another bulb in series of the circuit Hence,

voltage on each bulb becomes, $V=\frac{E}{2}$ for both thew bulbs.

where E= EMF of the battery and V= voltage Across the bulb.

and adding another bulb also introduces more resistance .

hence corrent also gets reduced.

$I=\frac{V}{R}$ as R becomes twice after adding another bulb.

Hence both V and I gets reduced making both the bulbs to glow dim.