in a circuit the internal resistance of cell is equal to external resistance. Of emf of the cell is 4v, then the potential difference across the terminals of the cell is

Open in App

Solution

Dear student,
Since both the resistors are same, therefore potential difference V+V =E
or V = E/2 = 4/2 = 2V

Regards

Suggest Corrections

Similar questions

A cell of emf 2.1 V and internal resistance 0.2 ohm is connected to a 4 ohm external resistance. The potential difference across the terminal of the cell is

Q. A cell of emf

E

is connected across a resistance

R

. The potential difference across the terminals of the cell is

V

. What is the internal resistance of the cell?

Q. The emf of a Daniel cell is

1.08 V .

When the terminals of the cells are connected to the resistance of

3 Ω

, the potential difference across the terminals is found to be

0.6 V

. Then the internal resistance of the cell is

Q. If the external resistance is equal to the internal resistance of a cell of emf E, the P.D across its terminals is :

Q. A cell of emf

E

and internal resistance

r

is connected in series with an external resistance

n r,

then the ratio of terminal potential difference to emf is

Join BYJU'S Learning Program

in a circuit the internal resistance of cell is equal to external resistance. Of emf of the cell is 4v, then the potential difference across the terminals of the cell is

Dear student, Since both the resistors are same, therefore potential difference V+V =E or V = E/2 = 4/2 = 2V Regards

Dear student,
Since both the resistors are same, therefore potential difference V+V =E
or V = E/2 = 4/2 = 2V

Regards